| 姓名 | 阿喀洛斯戰記 
|
|---|---|
| 图案 | The Akroan War |
| 类型 | 結界 ～傳紀 |
| 描述 | （於此傳紀進戰場時及於你抽牌步驟後，加一個學問指示物。到III後犧牲之。） I — 於阿喀洛斯戰記仍在戰場上的時段內，獲得目標生物的操控權。 II — 直到你的下一個回合，由對手操控的生物每次戰鬥若能攻擊，則必須攻擊。 III — 每個已橫置的生物各對本身造成等同於其力量的傷害。 |
| 艺术家 | Steven Belledin |
| 版 | 指挥官传奇：博德之门之战 #777 |
| Wallpaper |  download |
| 图片 |  download |
等级列表
No Rank
自己评分
阿喀洛斯戰記, 結界 ～傳紀, 设计者 Steven Belledin 首次发布于 Dec, 2019 在编辑中 Theros Beyond Death 并准确地印在 4 不同的形状. 见游戏 1 格式: Commander. 目前以最低价出售 ¥ 1.44.
这张卡牌《阿克洛斯战争》对于红色进攻牌组是有利的，它可以打乱对手的局面并暂时控制关键生物。在某些情况下，它可以是一个强大的工具，但根据牌组的具体策略，可能会有更好的选择，比如《背叛行为》可以立即窃取生物，或者像《炎刃斩击》这样的其他结界可以提供更一致的战斗优势。总的来说，《阿克洛斯战争》可以在专注于打乱生物和控制的牌组中发挥作用，但其效果可能会因整体游戏计划和元环境而异。
24/01/20
A chapter ability doesn’t trigger if a lore counter is put on a Saga that already had a number of lore counters greater than or equal to that chapter’s number. For example, the third lore counter put on a Saga causes the III chapter ability to trigger, but I and II won’t trigger again.
24/01/20
As a Saga enters the battlefield, its controller puts a lore counter on it. As your precombat main phase begins (immediately after your draw step), you put another lore counter on each Saga you control. Putting a lore counter on a Saga in either of these ways doesn’t use the stack.
24/01/20
Because a Saga isn’t sacrificed until after its last ability has resolved, you still control the creature you took with The Akroan War’s first ability while the last ability is resolving.
24/01/20
If multiple chapter abilities trigger at the same time, their controller puts them on the stack in any order. If any of them require targets, those targets are chosen as you put the abilities on the stack, before any of those abilities resolve.
24/01/20
If The Akroan War leaves the battlefield before its first ability resolves, you won’t gain control of the creature at all.
24/01/20
Once the number of lore counters on a Saga is greater than or equal to the greatest number among its chapter abilities, the Saga’s controller sacrifices it as soon as its chapter ability has left the stack, most likely by resolving or being countered. This state-based action doesn’t use the stack.
登录并加入对话
— 评论0
成为第一个发表评论的人